2y^2+36y+162=0

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Solution for 2y^2+36y+162=0 equation: 



2y^2+36y+162=0

a = 2; b = 36; c = +162;
Δ = b2-4ac
Δ = 362-4·2·162
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-36}{4}=-9$

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